Started 2 years ago by isak | 4 posts |
I have a form that allows users to upload up to 8 photos. The info from my form is displayed on a webpage. Is there a way to link to a "blank" photo by default? Otherwise, if a photo is not uploaded, I am getting a broken link graphic.
I already have several that have been uploaded via the form to my database.
Thanks.
redityo
Hi,
How you manage the code to display a photo from machform in your web page? I think you can use something like this :
$query = "select element_1 from ap_form_15";
$result = do_query($query);
while($row = do_fetch_result($result)){
if (empty($row['element_1'])) {
//code to show broken image or default image
} else {
//code to show the file from machform
}
}The flow is like this, first it will query a data from form 15 with element 1 as an upload field. Then if element_1 have empty value it will show broken image, otherwise it will show the photo from machform data.
MachForm Support
I am displaying my photos with this code:
[code]<img src="http://sandragunn.com/listings/data/form_7/files/<?php echo $row_rsVarpass['element_158']; ?>" alt="Sandra Gunn Properties in Houston | Houston Real Estate" />
<?php echo $row_rsVarpass['element_167']; ?>[/code]
I have 8 photos on the page and want to extend it to possibly 20.
If the value in a photo box is empty, I would like to default to an image called "transparent.gif" so I don't get the broken link image.
Is this do-able?
This is possible, however I'm afraid this one would be pretty much beyond MachForm.
It's actually pretty simple task, but require lot of coding and adjustments.
I suggest to get programmer to do this custom page for you. It should be a straight forward task for most PHP programmer.
MachForm Founder
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